document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=215910>Question 215910</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0131339966/algebrahomeworkh>Algebra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs to mix a solution containing 30% insecticede with a solution containing 50% insecticede to make 200 L of a solution that is 42% insecticide. How much of each solution should she use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #163108 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=163108\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of 30% insecticide needed<BR>\n" );
document.write( "Then (200-x)=amount of 50% insecticide needed\r<BR>\n" );
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document.write( "Now we know that the amount of pure insecticide that exists in the 30% solution(0.30x) plus the amount of pure insecticide that exists in the 50% solution (0.50(200-x)) has to equal the amount of pure isecticide that exists in the final mixture(0.42*200).  So, our equation to solve is:\r<BR>\n" );
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document.write( "0.30x+0.50(200-x)=0.42*200  get rid of parens and simplify<BR>\n" );
document.write( "0.30x+100-0.50x=84  subtract 100 from each side<BR>\n" );
document.write( "0.30x+100-100-0.50x=84-100  collect like terms<BR>\n" );
document.write( "-0.20x=-16  divide each side by -0.20<BR>\n" );
document.write( "x=80 L----------------------amount of 30% solution needed<BR>\n" );
document.write( "200-x=200-80=120 L---------------amount of 50% solution\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "0.30*80+0.50*120=0.42*200<BR>\n" );
document.write( "24+60=84<BR>\n" );
document.write( "84=84\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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