document.write( "Question 215895: Zelma is eighteen years older than her son. She was three times as old as he was one year ago. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #163080 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let Z = Zelma's present age and S = her son's present age. \n" ); document.write( "1) Z = S+18 \"Zelma (Z) is 18 years older than her son (S).\" \n" ); document.write( "2) Z-1 = 3(S-1) \"She was three times as old as he was one year ago.\" \n" ); document.write( "How old are they now? \n" ); document.write( "Rewrite equation 2) as: \n" ); document.write( "2a) Z = 3(S-1)+1 Simplify and substitute into equation 1) \n" ); document.write( "2b) Z = 3S-3+1 \n" ); document.write( "2c) Z = 3S-2 \n" ); document.write( "1a) 3S-2 = S+18 \n" ); document.write( "1b) 3S = S+20 \n" ); document.write( "1c) 2S = 20 \n" ); document.write( "1d) S = 10 This is her son's present age. \n" ); document.write( "Z = S+18 \n" ); document.write( "Z = 10+18 \n" ); document.write( "Z = 28 This is Zelma's present age. \n" ); document.write( " \n" ); document.write( " |