document.write( "Question 215895: Zelma is eighteen years older than her son. She was three times as old as he was one year ago. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #163080 by Earlsdon(6294)\"\" \"About 
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Let Z = Zelma's present age and S = her son's present age.
\n" ); document.write( "1) Z = S+18 \"Zelma (Z) is 18 years older than her son (S).\"
\n" ); document.write( "2) Z-1 = 3(S-1) \"She was three times as old as he was one year ago.\"
\n" ); document.write( "How old are they now?
\n" ); document.write( "Rewrite equation 2) as:
\n" ); document.write( "2a) Z = 3(S-1)+1 Simplify and substitute into equation 1)
\n" ); document.write( "2b) Z = 3S-3+1
\n" ); document.write( "2c) Z = 3S-2
\n" ); document.write( "1a) 3S-2 = S+18
\n" ); document.write( "1b) 3S = S+20
\n" ); document.write( "1c) 2S = 20
\n" ); document.write( "1d) S = 10 This is her son's present age.
\n" ); document.write( "Z = S+18
\n" ); document.write( "Z = 10+18
\n" ); document.write( "Z = 28 This is Zelma's present age.
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