document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=215746>Question 215746</A>: <I><SPAN STYLE=\"word-break: break-all;\"> to create a breakfast beverage, cherry juice in two concentrations, 19% and 60%, must be combined into a solution that will be mixed with another type of juice to produce the beverage. if 70 gallons of 19% juice is used, how many gallons of the 60% juice must be used to obtain a 50% cherry juice solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #163053 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=163053\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .60X+.19*70=.50(70+X)<BR>\n" );
document.write( ".60X+13.3=35+.5X<BR>\n" );
document.write( ".60X-.50X=35-13.3<BR>\n" );
document.write( ".10X=21.7<BR>\n" );
document.write( "X=21.7/.1<BR>\n" );
document.write( "X=217 GALLONS OF 60% IS USED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".6*217+.19*70=.5(70+217)<BR>\n" );
document.write( "130.2+13.3=.5*287<BR>\n" );
document.write( "143.5=143.5 </SPAN>\n" );
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