document.write( "Question 215817: A rectangle is 5 feet longer than it is wide. The perimiter of the rectangle is 24 feet. What is the length of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #163050 by checkley77(12844)\"\" \"About 
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L=W+5
\n" ); document.write( "2L+2W=24
\n" ); document.write( "2(W+5)+2W=24
\n" ); document.write( "2W+10+2W=24
\n" ); document.write( "4W=24-10
\n" ); document.write( "4W=14
\n" ); document.write( "W=14/4
\n" ); document.write( "W=3.5 FT. IS THE WIDTH.
\n" ); document.write( "L=3.5+5=8.5 IS THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*8.5+2*3.5=24
\n" ); document.write( "17+7=24
\n" ); document.write( "24=24
\n" ); document.write( "
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