document.write( "Question 215773: What are three consecutive integers such that the sum of twice the smallest and three times the largest is 126? \n" ); document.write( "

Algebra.Com's Answer #163005 by Earlsdon(6294) $\"\"$ $\"About$

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Let x = the first (smallest) integer, then (x+2) is the next consecutive integer and (x+3) is the third (largest) consecutive integer.
\n" ); document.write( " $\"2x%2B3%28x%2B2%29+=+126\"$ \"...the sum of twice the smallest integer and three times the largest is 126.\"
\n" ); document.write( " $\"2x%2B3x%2B6+=+126\"$
\n" ); document.write( " $\"5x%2B6+=+126\"$ Subtract 6 from both sides.
\n" ); document.write( " $\"5x+=+120\"$ Divide both sides by 5.
\n" ); document.write( " $\"x+=+24\"$ and $\"x%2B1+=+25\"$ , $\"x%2B2+=+26\"$
\n" ); document.write( "The three consecutive integers are: 24, 25, and 26. \n" ); document.write( "

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