document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=215740>Question 215740</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the standard form of the equation of the circle with the endpoints of the diameter at the points of (5,2) and (-9,6)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #162989 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=162989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the standard form of the equation of the circle with the endpoints of the diameter at the points of (5,2) and (-9,6) <BR>\n" );
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document.write( "The diameter is the distance between the 2 points.<BR>\n" );
document.write( "d^2 = diffy^2 + diffx^2 = 4^2 + 14^2<BR>\n" );
document.write( "d^2 = 212<BR>\n" );
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document.write( "The center is the midpoint.  Find the average of x and y separately.<BR>\n" );
document.write( "x: (5-9)/2 = -2<BR>\n" );
document.write( "y: (2+6)/2 = 4<BR>\n" );
document.write( "Center at (2,-4)<BR>\n" );
document.write( "(x-2)^2 + (y-4)^2 = 212 is the circle<BR>\n" );
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