document.write( "Question 29478: Jim can run 5 miles per hour on level ground on a still day. One windy day, he runs 15 miles with the wind and in the same amount of time runs 4 miles against the wind. What is the rate of the wind?
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document.write( "This is what I have
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document.write( "x= rate of wind
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document.write( "5 + x = running with the wind
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document.write( "5 - x = running against the wind
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document.write( "then I have
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document.write( "15/5+x = distance on a windy day running with the wind
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document.write( "4/5-x = distance on a windy day running against the wind
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document.write( "Am I on the right track? When I solve for x I get a decimal of 1.89 or 1.90
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document.write( "thanks for your help \n" );
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Algebra.Com's Answer #16292 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! You were almost there \n" ); document.write( "You are given two situatiuons and the common element is time \n" ); document.write( "let r = runners rate on a still day \n" ); document.write( "let w = rate of the wind \n" ); document.write( "let t = time \n" ); document.write( "running with the wind the combined rate is \n" ); document.write( "r + w \n" ); document.write( "running against the wind the combined rate is \n" ); document.write( "r - w \n" ); document.write( "distance = rate x time \n" ); document.write( "[1] 15 = (r + w) x t \n" ); document.write( "[2] 4 = (r - w) x t \n" ); document.write( "divide both sides of [1] by (r + w) \n" ); document.write( "divide both sides of [2] by (r - w) \n" ); document.write( "15 / (r + w) = t \n" ); document.write( "4 / (r - w) = t \n" ); document.write( "since they're both equal to t, set them equal to eachother \n" ); document.write( "15/(r + w) = 4 / (r - w) \n" ); document.write( "from the problem description, r = 5 \n" ); document.write( "15 / (5 + w) = 4 / (5 - w) \n" ); document.write( "cross-multiply \n" ); document.write( "15(5 - w) = 4(5 + w) \n" ); document.write( "75 - 15w = 20 + 4w \n" ); document.write( "19w = 55 \n" ); document.write( "w = 2.895 \n" ); document.write( "check \n" ); document.write( "15(5 - 55/19) = 4(5 + 55/19) \n" ); document.write( "15(95 - 55)/19 = 4(95 + 55)/19 \n" ); document.write( "15 x 40 / 19 = 4 x 150 / 19 \n" ); document.write( "multiply both sides by 19 \n" ); document.write( "divide both sides by 150 \n" ); document.write( "4 = 4 \n" ); document.write( "OK \n" ); document.write( "where you went wrong was here \n" ); document.write( "------- \n" ); document.write( "15/5+x = distance on a windy day running with the wind \n" ); document.write( "4/5-x = distance on a windy day running against the wind \n" ); document.write( "------- \n" ); document.write( "sould have read \n" ); document.write( "\"TIME on a windy day running with the wind\" and \n" ); document.write( "\"TIME on a windy day running against the wind\" \n" ); document.write( " |