document.write( "Question 215506This question is from textbook Elementary & Intermediate Algebra
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document.write( ": The golden ratio. The ancient Greeks thought that the most pleasing shape for a rectangle was one for which the ratio of the length to the width was approximately 8 to 5, the golden ratio. If the length of a rectangular painting is 2 ft longer than its width, then for what dimensions would the length and width have the golden ratio? \n" );
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Algebra.Com's Answer #162912 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The golden ratio. The ancient Greeks thought that the most pleasing shape for a \n" ); document.write( " rectangle was one for which the ratio of the length to the width was approximately 8 to 5, the golden ratio. \n" ); document.write( "If the length of a rectangular painting is 2 ft longer than its width, then for \n" ); document.write( " what dimensions would the length and width have the golden ratio? \n" ); document.write( ": \n" ); document.write( "Let x = width of the painting \n" ); document.write( "then \n" ); document.write( "(x+2) = length of the painting \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Cross multiply, results \n" ); document.write( "8x = 5(x+2) \n" ); document.write( ": \n" ); document.write( "8x = 5x + 10 \n" ); document.write( ": \n" ); document.write( "8x - 5x = 10 \n" ); document.write( ": \n" ); document.write( "3x = 10 \n" ); document.write( "x = \n" ); document.write( "x = 3 \n" ); document.write( "and \n" ); document.write( "5 \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution: \n" ); document.write( "5/8 = .625 \n" ); document.write( "3.3333/5.3333 = .64998 ~ .625 \n" ); document.write( " |