document.write( "Question 215506This question is from textbook Elementary & Intermediate Algebra
\n" ); document.write( ": The golden ratio. The ancient Greeks thought that the most pleasing shape for a rectangle was one for which the ratio of the length to the width was approximately 8 to 5, the golden ratio. If the length of a rectangular painting is 2 ft longer than its width, then for what dimensions would the length and width have the golden ratio? \n" ); document.write( "
Algebra.Com's Answer #162912 by ankor@dixie-net.com(22740)\"\" \"About 
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The golden ratio. The ancient Greeks thought that the most pleasing shape for a
\n" ); document.write( " rectangle was one for which the ratio of the length to the width was approximately 8 to 5, the golden ratio.
\n" ); document.write( "If the length of a rectangular painting is 2 ft longer than its width, then for
\n" ); document.write( " what dimensions would the length and width have the golden ratio?
\n" ); document.write( ":
\n" ); document.write( "Let x = width of the painting
\n" ); document.write( "then
\n" ); document.write( "(x+2) = length of the painting
\n" ); document.write( ":
\n" ); document.write( "\"x%2F%28%28x%2B2%29%29\" = \"5%2F8\"
\n" ); document.write( "Cross multiply, results
\n" ); document.write( "8x = 5(x+2)
\n" ); document.write( ":
\n" ); document.write( "8x = 5x + 10
\n" ); document.write( ":
\n" ); document.write( "8x - 5x = 10
\n" ); document.write( ":
\n" ); document.write( "3x = 10
\n" ); document.write( "x = \"10%2F3\"
\n" ); document.write( "x = 3\"1%2F3\" units wide
\n" ); document.write( "and
\n" ); document.write( "5\"1%2F3\" units long
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check solution:
\n" ); document.write( "5/8 = .625
\n" ); document.write( "3.3333/5.3333 = .64998 ~ .625
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