document.write( "Question 215529: How many gallons of 50% antifreeze solution must be mixed with 70 gallons of 25% antifreeze to get a mixture that is 40% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #162849 by nerdybill(7384) You can put this solution on YOUR website! How many gallons of 50% antifreeze solution must be mixed with 70 gallons of 25% antifreeze to get a mixture that is 40% antifreeze? \n" ); document.write( ". \n" ); document.write( "Let x = amount of 50% antifreeze added \n" ); document.write( "then \n" ); document.write( ".50x + .25(70) = .40(70 + x) \n" ); document.write( ".50x + 17.5 = 28 + .40x \n" ); document.write( ".50x = 10.5 + .40x \n" ); document.write( ".10x = 10.5 \n" ); document.write( "x = 10.5/.10 \n" ); document.write( "x = 105 gallons\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |