document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=215483>Question 215483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The equation of the line that goes through the point ( 3 ,7 ) and is perpendicular to the line 3 x + 2 y = 4 can be written in the form y = mx+b where m  is: and where b is: <BR>\n" );
document.write( "So, I got 3x + 2y = 4<BR>\n" );
document.write( "2y = 4 - 3x<BR>\n" );
document.write( "y = (4 - 3x)/2<BR>\n" );
document.write( "so m=2/3<BR>\n" );
document.write( "then i plugged everything and got<BR>\n" );
document.write( "y - 7 = 2/3(x + 3)<BR>\n" );
document.write( "y - 7 = 2/3x + 2<BR>\n" );
document.write( "y = 2/3x + 2 + 7<BR>\n" );
document.write( "y = 2/3x + 9<BR>\n" );
document.write( "Somehow its wrong, can anyone help? Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #162830 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=162830\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ok, you've got the slope of the new line correct.  The negative reciprocal of the given line which has a slope: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m+=+-3%2F2 ALIGN=MIDDLE  ALT=\"m+=+-3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > is, of course, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now you can write:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%282%2F3%29x%2Bb ALIGN=MIDDLE  ALT=\"y+=+%282%2F3%29x%2Bb\"   DISABLED_style= \"max-width:90%; height:auto;\" > In order to find b, the y-intercept, substitute the x- and y-coordinates of the point (3, 7) through which this line passes.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7+=+%282%2F3%29%283%29%2Bb ALIGN=MIDDLE  ALT=\"7+=+%282%2F3%29%283%29%2Bb\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7+=+2%2Bb ALIGN=MIDDLE  ALT=\"7+=+2%2Bb\"   DISABLED_style= \"max-width:90%; height:auto;\" > so...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+5 ALIGN=MIDDLE  ALT=\"b+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "The final equation is:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28y+=+%282%2F3%29x%2B5%29 ALIGN=MIDDLE  ALT=\"highlight%28y+=+%282%2F3%29x%2B5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );