document.write( "Question 215483: The equation of the line that goes through the point ( 3 ,7 ) and is perpendicular to the line 3 x + 2 y = 4 can be written in the form y = mx+b where m is: and where b is:
\n" ); document.write( "So, I got 3x + 2y = 4
\n" ); document.write( "2y = 4 - 3x
\n" ); document.write( "y = (4 - 3x)/2
\n" ); document.write( "so m=2/3
\n" ); document.write( "then i plugged everything and got
\n" ); document.write( "y - 7 = 2/3(x + 3)
\n" ); document.write( "y - 7 = 2/3x + 2
\n" ); document.write( "y = 2/3x + 2 + 7
\n" ); document.write( "y = 2/3x + 9
\n" ); document.write( "Somehow its wrong, can anyone help? Thank you!
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Algebra.Com's Answer #162825 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
The equation of the line that goes through the point (3,7) and is perpendicular to the line 3 x + 2 y = 4 can be written in the form y = mx+b where m is: and where b is:
\n" ); document.write( "So, I got 3x + 2y = 4
\n" ); document.write( "2y = 4 - 3x
\n" ); document.write( "y = (4 - 3x)/2
\n" ); document.write( "************ y = (-3/2)x + 2
\n" ); document.write( "m = -3/2
\n" ); document.write( "--------
\n" ); document.write( "so m=2/3 ** That's the slope of lines perpendicular, the neg inverse of -3/2. Odd that you would have gotten the right answer using 2/3.
\n" ); document.write( "----------
\n" ); document.write( "then i plugged everything and got
\n" ); document.write( "y - 7 = 2/3(x + 3)
\n" ); document.write( "**************** y-7 = (2/3)(x - 3) You had (x+3)
\n" ); document.write( "y - 7 = 2/3x - 2
\n" ); document.write( "y = (2/3)x - 2 + 7
\n" ); document.write( "y = (2/3)x + 5
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