document.write( "Question 215462This question is from textbook Geometry for Enjoyment and Challenge
\n" ); document.write( ": Dear Tutor, please help me with this math question as best as you can. I do not understand it that well....\r
\n" ); document.write( "\n" ); document.write( " The measure of the supplement of an angle exceeds 3 times the measure of the complement of the angle by 10. Find the measure of the complement. \r
\n" ); document.write( "\n" ); document.write( "I tired lots of different equations, like 3x+10=90 and 6x+20=180 but I have no idea how to do it. \r
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Algebra.Com's Answer #162802 by vleith(2983)\"\" \"About 
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The measure of the supplement of an angle exceeds 3 times the measure of the complement of the angle by 10. Find the measure of the complement. \r
\n" ); document.write( "\n" ); document.write( "Let x be the angle. Then 90-x is the complement and 180-x is the supplement.
\n" ); document.write( "You are told \"%28180-x%29+=+3%2A%2890-x%29+%2B+10\"
\n" ); document.write( "\"180+-x+=+270+-+3x+%2B+10\"
\n" ); document.write( "\"2x+=+90%2B10\"
\n" ); document.write( "\"2x+=+100\"
\n" ); document.write( "\"x+=+50\"
\n" ); document.write( "So the complement is 90-50 = 40
\n" ); document.write( "Check your answer, the supplement would be 180-50 = 130
\n" ); document.write( "Is 130 = 3*40 + 10???
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