document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=215399>Question 215399</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a 20% solution of fertilizer is to be mixed with a 80% solution of fertilizer in order to get 120 gallons of a 60% solution. how many gallons of the 20% solution and 80% solution should be mixed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #162744 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=162744\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .20x+.80*120=.60(120+x)<BR>\n" );
document.write( ".20x+96=72+.60x<BR>\n" );
document.write( ".20x-.60x=72-96<BR>\n" );
document.write( "-.40x=-24<BR>\n" );
document.write( "x=-24/-.40<BR>\n" );
document.write( "x=60 gallons of 20% solution is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".20*60+.80*120=.60(120+60)<BR>\n" );
document.write( "12+96=.60*180<BR>\n" );
document.write( "108=108 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );