document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=215279>Question 215279</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A mixture containing 8% salt is to be mixed with 40 mL of a mixture that is 20% salt, in order to obtain a solution that is 12% salt. How much of the first solution must be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #162740 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=162740\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .08x+.20*40=.12(40+x)<BR>\n" );
document.write( ".08x+8=4.8-.12x<BR>\n" );
document.write( ".08x-.12x=4.8-8<BR>\n" );
document.write( "-.04x=-3.2<BR>\n" );
document.write( "x=-3.2/.04<BR>\n" );
document.write( "x=80 ml of 8% salt is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".08*80+.20*40=.12(40+80)<BR>\n" );
document.write( "6.4+8=.12*120<BR>\n" );
document.write( "14.4=14.4<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );