document.write( "Question 215375: Two cards are drawn in succession without replacement from a standard deck of 52 playing cards. What is the probability that the first card drawn was a diamond given that the second card drawn was not a diamond? (Round your answer to four decimal places.) \r
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Algebra.Com's Answer #162739 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
Two cards are drawn in succession without replacement from a standard deck of 52 playing cards. What is the probability that the first card drawn was a diamond given that the second card drawn was not a diamond? (Round your answer to four decimal places.)
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document.write( "There are 13 diamonds and 39 non-diamonds in a deck of 52.\r\n" );
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document.write( "The formula for a conditional probability is\r\n" );
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document.write( "\"P%28%22A%7CB%22%29+=+P%28A_and_B%29%2FP%28B%29\"\r\n" );
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document.write( "where \"%22A%7CB%22\" means \"A given B\"\r\n" );
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document.write( "Let A be \"the first card was a diamond\"\r\n" );
document.write( "Let B be \"the second card was a non-diamond\"\r\n" );
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document.write( "The probability on the left of the formula is a CONDITIONAL \r\n" );
document.write( "probability, but the two probabilities on the right are NOT.  \r\n" );
document.write( "We are not to assume we are given anything when we calculate \r\n" );
document.write( "the right side.\r\n" );
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document.write( "\"AND\" indicates that we are to multiply and \"OR\" indicates\r\n" );
document.write( "that we are to add.\r\n" );
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document.write( "\"P%28A_and_B%29+=+%2813%2F52%29%2839%2F51%29=+13%2F68\"\r\n" );
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document.write( "Going back to the conditional probability formula:\r\n" );
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document.write( "\"P%28%22A%7CB%22%29+=+P%28A_and_B%29%2FP%28B%29=%2813%2F68%29%2F%283%2F4%29=13%2F51\"\r\n" );
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document.write( "To ask me anything you don't understand about this problem, email\r\n" );
document.write( "me at AnlytcPhil@aol.com, or ask me in your thank-you note.\r\n" );
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document.write( "Edwin
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