document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=215321>Question 215321</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many pounds of an alloy of 20% silver must be melted with 50lbs of an alloy with 30% silver in order to get an alloy of 27% silver </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #162734 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=162734\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .20x+.30*50=.27(50+x)<BR>\n" );
document.write( ".20x+15=13.5+.27x<BR>\n" );
document.write( ".20x-.27x=13.5-15<BR>\n" );
document.write( "-.07x=-1.5<BR>\n" );
document.write( "x=-1.5/-.07<BR>\n" );
document.write( "x=21.43 pounds of 20% silver is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".20*21.43+.30*50=.27(50+21.43)<BR>\n" );
document.write( "4.286+15=.27*71.43<BR>\n" );
document.write( "19.286=19.286 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );