document.write( "Question 215375: Two cards are drawn in succession without replacement from a standard deck of 52 playing cards. What is the probability that the first card drawn was a diamond given that the second card drawn was not a diamond? (Round your answer to four decimal places.) \r
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document.write( "i cant seem to get this problem right as simple as it sounds!!!!!! \n" );
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Algebra.Com's Answer #162733 by drj(1380)![]() ![]() You can put this solution on YOUR website! Two cards are drawn in succession without replacement from a standard deck of 52 playing cards. What is the probability that the first card drawn was a diamond given that the second card drawn was not a diamond? (Round your answer to four decimal places.) \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 1. Let P(A) be the probability of a diamond and P(B) is not a diamond or 1-P(A) for the first card. For the first card P(A)=13/52=0.25 and P(B)=1-P(A)=0.75\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 2. Let Probability of a diamond occurring in the second card given that probaility of diamond occurring in the first card be given as P(A|B)= P(A and B)/P(B).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 3. The probability of a diamond in the second card is P(A and B)=13/51. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 4. P(A|B)=P(A and B)/P(B)= (13/51)/((39/52)=0.3399\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 5. Answer is P(is a diamond on second card |not a diamond on first card)=P(A|B)=0.3399\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For Step-By-Step videos in Circuit Analysis and Differential Equation please visit http://www.FreedomUniversity.TV\r \n" ); document.write( "\n" ); document.write( "For Free Step-By-Step Videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Respectfully, \n" ); document.write( "Dr J\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |