document.write( "Question 215309: The sum of thre numbers is 40. One number is 5 more than the second number. It is twice the third number. What are the numbers. \n" ); document.write( "
Algebra.Com's Answer #162731 by MathTherapy(10557)\"\" \"About 
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The sum of thre numbers is 40. One number is 5 more than the second number. It is twice the third number. What are the numbers.\r
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\n" ); document.write( "\n" ); document.write( "Let the second number be S\r
\n" ); document.write( "\n" ); document.write( "Then the first number is S + 5 since it is given that it's 5 more than the second number\r
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\n" ); document.write( "\n" ); document.write( "And, since it's given that the 1st number is also twice the 3rd number, then the 3rd number = \"%28S+%2B+5%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Since it's also given that the 3 numbers total 40, then we'll have: \"S+%2B+S+%2B+5+%2B+%28S+%2B+5%29%2F2+=+40\"\r
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\n" ); document.write( "\n" ); document.write( "2S + 2S + 10 + S + 5 = 80 ------- Multiplying by LCD, 2\r
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\n" ); document.write( "\n" ); document.write( "5S + 15 = 80\r
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\n" ); document.write( "\n" ); document.write( "5S = 65\r
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\n" ); document.write( "\n" ); document.write( "\"S+=+65%2F5+=+13\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the first number, or S + 5 is \"highlight_green%2818%29\" (13 + 5), the second number, or S is \"highlight_green%2813%29\", and the third \"highlight_green%289%29\" (\"18%2F2\").
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