document.write( "Question 215309: The sum of thre numbers is 40. One number is 5 more than the second number. It is twice the third number. What are the numbers. \n" ); document.write( "
Algebra.Com's Answer #162731 by MathTherapy(10557) You can put this solution on YOUR website! The sum of thre numbers is 40. One number is 5 more than the second number. It is twice the third number. What are the numbers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let the second number be S\r \n" ); document.write( "\n" ); document.write( "Then the first number is S + 5 since it is given that it's 5 more than the second number\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And, since it's given that the 1st number is also twice the 3rd number, then the 3rd number = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since it's also given that the 3 numbers total 40, then we'll have: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2S + 2S + 10 + S + 5 = 80 ------- Multiplying by LCD, 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5S + 15 = 80\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5S = 65\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, the first number, or S + 5 is |