document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=215299>Question 215299</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a mixture containing 8% salt is to be mixed with 40mL of a mixture that is 20% salt, in order to obtain a solution that is 12% salt. How much of the first solution must be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #162669 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=162669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let  x  =  added  solution<BR>\n" );
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document.write( ".08x + .2(40) = .12(x+40),,,,,salt  balance<BR>\n" );
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document.write( ".08x +8 = .12x +4.8<BR>\n" );
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document.write( "3.2 = .04x<BR>\n" );
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document.write( "80 = x,,,,,in  ml<BR>\n" );
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document.write( "check,,,,.08(80) +.2(40)= .12(120) = 14.4 </SPAN>\n" );
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