document.write( "Question 29425: ln(x+2)=ln(2x-1)+3 \n" ); document.write( "
Algebra.Com's Answer #16266 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! ln(x+2)=ln(2x-1)+3 \n" ); document.write( "ln(x+2) - ln(2x-1) = 3 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so either leave this as it is...it is the PRECISE answer. If you use a calulator, you will have to round up the answer, since it is a never-ending number... x = 0.563822605 to 9dp.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "PS the other solution by sdmmadam is wrong because on line 3 the \"ln\" becomes \"log\" which is wrong. The actual mechanics is correct though...just that the x value is wrong.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |