document.write( "Question 29425: ln(x+2)=ln(2x-1)+3 \n" ); document.write( "
Algebra.Com's Answer #16266 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
ln(x+2)=ln(2x-1)+3
\n" ); document.write( "ln(x+2) - ln(2x-1) = 3
\n" ); document.write( "\"+ln%28%28x%2B2%29%2F%282x-1%29%29+=+3+\"
\n" ); document.write( "\"+%28x%2B2%29%2F%282x-1%29+=+e%5E3+\"\r
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\n" ); document.write( "\n" ); document.write( "Now, \"e%5E3\" is just a number...JUST a number!\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "\"+%28x%2B2%29+=+e%5E3%282x-1%29+\"
\n" ); document.write( "\"+x%2B2+=+2e%5E3x-e%5E3+\"
\n" ); document.write( "\"+x%2B2-2e%5E3x+=+-e%5E3+\"
\n" ); document.write( "\"+x-2e%5E3x+=+-2-e%5E3+\"
\n" ); document.write( "\"+x%281-2e%5E3%29+=+-2-e%5E3+\"
\n" ); document.write( "\"+x+=+%28-2-e%5E3%29%2F%281-2e%5E3%29+\"
\n" ); document.write( "\"+x+=+%28-%282%2Be%5E3%29%29%2F%28-%282e%5E3-1%29%29+\"
\n" ); document.write( "\"+x+=+%282%2Be%5E3%29%2F%282e%5E3-1%29+\"\r
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\n" ); document.write( "\n" ); document.write( "so either leave this as it is...it is the PRECISE answer. If you use a calulator, you will have to round up the answer, since it is a never-ending number... x = 0.563822605 to 9dp.\r
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\n" ); document.write( "\n" ); document.write( "PS the other solution by sdmmadam is wrong because on line 3 the \"ln\" becomes \"log\" which is wrong. The actual mechanics is correct though...just that the x value is wrong.\r
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\n" ); document.write( "\n" ); document.write( "jon.
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