document.write( "Question 215265: I would really appreciate anyone who would be willing to help me answer it!\r
\n" ); document.write( "\n" ); document.write( "Vivian is 5 years older than Carmen. When Vivian's age is doubled and then subtracted from four times Carmen's age, the result is Carmen's present age, increased by 10. How old is each?
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Algebra.Com's Answer #162656 by tutor_paul(519)\"\" \"About 
You can put this solution on YOUR website!
Write 2 Equations based on the information given. Let V=Vivian's age and C=Carmen's age:
\n" ); document.write( "From the first sentence:
\n" ); document.write( "Equation #1:\"V=C%2B5\"
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\n" ); document.write( "From the second sentence:
\n" ); document.write( "\"4C-2V=C%2B10\"
\n" ); document.write( "Simplify:
\n" ); document.write( "Equation #2:\"3C-2V=10\"
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\n" ); document.write( "Now you have 2 equations with 2 unknowns.
\n" ); document.write( "Substitute Equation #1 into Equation #2:
\n" ); document.write( "\"3C-2%28C%2B5%29=10\"
\n" ); document.write( "Solve for C:
\n" ); document.write( "\"3C-2C-10=10\"
\n" ); document.write( "\"highlight%28C=20%29\"
\n" ); document.write( "Next, plug this value of C into Equation #1 and solve for V:
\n" ); document.write( "\"highlight%28V=25%29\"
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\n" ); document.write( "As a final check, plug these results back into Equation #1 and Equation #2 to be sure they still hold true. I'll leave that part to you.
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\n" ); document.write( "Good Luck,
\n" ); document.write( "tutor_paul@yahoo.com\r
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