document.write( "Question 215177: A 96% solution of sulfuric acid is to be diluted with distilled water to make a 90% solution of sulfuric acid. How many litres of the orginal solution and how many litres of water are necessary to make 12.0L of the 90% solution? \n" ); document.write( "
Algebra.Com's Answer #162573 by ankor@dixie-net.com(22740)\"\" \"About 
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A 96% solution of sulfuric acid is to be diluted with distilled water to make
\n" ); document.write( " a 90% solution of sulfuric acid. How many litres of the original solution
\n" ); document.write( " and how many litres of water are necessary to make 12.0L of the 90% solution?
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\n" ); document.write( "Let x = amt of water
\n" ); document.write( "then
\n" ); document.write( "(12-x) = amt of 96% sulfuric acid
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\n" ); document.write( ".96(12-x) = .90(12)
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\n" ); document.write( "11.52 - .96x = 10.8
\n" ); document.write( ":
\n" ); document.write( "11.52 - 10.8 = .96x
\n" ); document.write( ":
\n" ); document.write( ".72 = .96x
\n" ); document.write( "x = (.72/.96)
\n" ); document.write( "x = .75 liters of water added to 11.25 liters of sulfuric acid
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\n" ); document.write( ":
\n" ); document.write( "Check by finding the amt of sulfuric acid (amt should be unchanged)
\n" ); document.write( ".96(11.25) = .90(12)
\n" ); document.write( "10.8 = 10.8 \n" ); document.write( "
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