document.write( "Question 215162: A ball is thrown upward from ground level with an initial velocity of 108 ft per sec. Its height H in feet after T seconds is given by the equation \"+++H=+-16T%5E2+%2B+108T\". At what time will the ball hit the ground? \n" ); document.write( "
Algebra.Com's Answer #162572 by Edwin McCravy(20056)\"\" \"About 
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A ball is thrown upward from ground level with an initial velocity of 108 ft per sec. Its height H in feet after T seconds is given by the equation \"+++H=+-16T%5E2+%2B+108T\". At what time will the ball hit the ground?
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document.write( "When the ball hits the ground, its height above the ground equals zero. \r\n" );
document.write( "So just substitute H=0 and  \r\n" );
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document.write( "\"+++H=+-16T%5E2+%2B+108T\"\r\n" );
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document.write( "Substituting,\r\n" );
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document.write( "\"+++0=+-16T%5E2+%2B+108T\"\r\n" );
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document.write( "Adding \"16T%5E2-108T\" to both sides:\r\n" );
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document.write( "\"+++16T%5E2+-+108T=0\"\r\n" );
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document.write( "Factor \"4T\" out of the left side:\r\n" );
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document.write( "\"4T%284T%5E2-27%29=0\"\r\n" );
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document.write( "Set each factor = 0:\r\n" );
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document.write( "\"4T=0\"\r\n" );
document.write( "\"T=0%2F4\"\r\n" );
document.write( "\"T=0\"\r\n" );
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document.write( "\"4T%5E2-27=0\"\r\n" );
document.write( "\"4T%5E2=27\"\r\n" );
document.write( "\"T%5E2=27%2F4\"\r\n" );
document.write( "\"T=sqrt%2827%2F4%29\"\r\n" );
document.write( "\"T=sqrt%2827%29%2Fsqrt%284%29\"\r\n" );
document.write( "\"T=sqrt%2827%29%2F2\"\r\n" );
document.write( "\"T=sqrt%289%2A3%29%2F2\"\r\n" );
document.write( "\"T=%28sqrt%289%29%2Asqrt%283%29%29%2F2\"\r\n" );
document.write( "\"T=%283sqrt%283%29%29%2F2=+2.598076211\"\r\n" );
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document.write( "which means the ball is on the ground when time is 0,\r\n" );
document.write( "that is, before the ball first starts upward, and again at when\r\n" );
document.write( "when it comes back down to the ground 2.6 seconds later.\r\n" );
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document.write( "Edwin
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