document.write( "Question 215090This question is from textbook Elementary Statistics
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document.write( ": The average yearly cost per household of owning a dog is $186.80. Suppose that we randomly select 50 households that own a dog. What is the probability that the sample mean for these 50 households is less than $175.00? assume o=$32\r
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document.write( "* The book i am using gave me the formula value-mean/standard diveation. But me and my mother have been looking at this problem for at least 30 minutes and still just cant figure it out. plzz help me!! \n" );
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Algebra.Com's Answer #162568 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The average yearly cost per household of owning a dog is $186.80. Suppose that we randomly select 50 households that own a dog. What is the probability that the sample mean for these 50 households is less than $175.00? assume o=$32 \n" ); document.write( "-------------------------------------------- \n" ); document.write( "Find the z-value of 175.00: \n" ); document.write( "z(174) = (175-186.80)/[32/sqrt(50)] = -11.80/[4.5255] = -2.6075 \n" ); document.write( "---------------------------------- \n" ); document.write( "P(x < 175) = P(z < -2.6075) = 0.00456 \n" ); document.write( "====================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |