document.write( "Question 215108: How do I reduce this to simplest terms? 7m/2m+14 . 3m+21/9m
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\n" ); document.write( "\n" ); document.write( "I tried dividing by m in the first part of the equation and wasn't sure if i should use the m as the greatest common factor like m(7) over m( 2+14) is that right at all? I did the same thing on the other part of the equation dividing by 3m getting 3m(1+21) over 3m(3). Can you tell me if I am on the right track, and how to correctly solve this equation?
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Algebra.Com's Answer #162541 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%28%287m%29%2F%282m%2B14%29%29%28%283m%2B21%29%2F%289m%29%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28%287m%29%2F%282%28m%2B7%29%29%29%28%283m%2B21%29%2F%289m%29%29\" Factor \"2m%2B14\" to get \"2%28m%2B7%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%287m%29%2F%282%28m%2B7%29%29%29%28%283%28m%2B7%29%29%2F%289m%29%29\" Factor \"3m%2B21\" to get \"3%28m%2B7%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%287m%29%2F%282%28m%2B7%29%29%29%28%283%28m%2B7%29%29%2F%283%2A3m%29%29\" Factor \"9m\" to get \"3%2A3m\"\r
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\n" ); document.write( "\n" ); document.write( "\"%287%2A3m%28m%2B7%29%29%2F%282%2A3%2A3m%28m%2B7%29%29\" Combine the fractions.\r
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\n" ); document.write( "\n" ); document.write( " Highlight the common terms.\r
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\n" ); document.write( "\n" ); document.write( " Cancel out the common terms.\r
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\n" ); document.write( "\n" ); document.write( "\"7%2F%282%2A3%29\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"7%2F6\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So \"%28%287m%29%2F%282m%2B14%29%29%28%283m%2B21%29%2F%289m%29%29\" simplifies to \"7%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%28%287m%29%2F%282m%2B14%29%29%28%283m%2B21%29%2F%289m%29%29=7%2F6\"\r
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