document.write( "Question 215091: I'm having trouble completing the square and finding the vertex of the following function:\r
\n" ); document.write( "\n" ); document.write( "\"+y=-4x%5E2-12x%2B6+\"\r
\n" ); document.write( "\n" ); document.write( "Is making it into this the correct way to go about it??\r
\n" ); document.write( "\n" ); document.write( "\"+4%28x%5E2%2B3x-1.5%29+\"\r
\n" ); document.write( "\n" ); document.write( "Please help me!
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Algebra.Com's Answer #162524 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
finding the vertex of the following function:\r
\n" ); document.write( "\n" ); document.write( " y=-4x^2-12x+6 \r
\n" ); document.write( "\n" ); document.write( "--------------------------------
\n" ); document.write( "Rearrange:
\n" ); document.write( "-4x^2 - 12x = y -6
\n" ); document.write( "Factor out the -4
\n" ); document.write( "-4(x^2 + 3x + ?) = y-6 -4?
\n" ); document.write( "---
\n" ); document.write( "-4(x^2 + 3x + (3/2)^2) = y - 6 -4(9/4)
\n" ); document.write( "---
\n" ); document.write( "-4(x+(3/2))^2 = y -6 -9
\n" ); document.write( "---
\n" ); document.write( "-4(x+(3/2))^2 = y-15
\n" ); document.write( "---
\n" ); document.write( "Vertex at (-3/2 , 15)
\n" ); document.write( "---
\n" ); document.write( "\"graph%28400%2C300%2C-10%2C10%2C-10%2C20%2C-4x%5E2-12x%2B6%29\"
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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