document.write( "Question 215082: I have been stuck on this for over an hour!\r
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document.write( "If r varies inversely with w - 1. If r = 3/50 when w = 3, find r when w is 10. \r
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document.write( "A75
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document.write( "B10
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document.write( "C175
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document.write( "D1/75
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document.write( "E1/750
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document.write( "F1/175\r
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document.write( "I think I understand the process but can't find the solution to this one! \n" );
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Algebra.Com's Answer #162514 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! If r varies inversely with w - 1. If r = 3/50 when w = 3, find r when w is 10. \n" ); document.write( "A75 \n" ); document.write( "B10 \n" ); document.write( "C175 \n" ); document.write( "D1/75 \n" ); document.write( "E1/750 \n" ); document.write( "F1/175 \n" ); document.write( "------------ \n" ); document.write( "r = k/(w-1) k is some constant \n" ); document.write( "3/50 = k/(3-1) = k/2 \n" ); document.write( "k = 3/25 \n" ); document.write( "------------------- \n" ); document.write( "r = (3/25)/(10-1) \n" ); document.write( "r = 1/75 \n" ); document.write( " \n" ); document.write( " |