document.write( "Question 215082: I have been stuck on this for over an hour!\r
\n" ); document.write( "\n" ); document.write( "If r varies inversely with w - 1. If r = 3/50 when w = 3, find r when w is 10. \r
\n" ); document.write( "\n" ); document.write( "A75
\n" ); document.write( "B10
\n" ); document.write( "C175
\n" ); document.write( "D1/75
\n" ); document.write( "E1/750
\n" ); document.write( "F1/175\r
\n" ); document.write( "\n" ); document.write( "I think I understand the process but can't find the solution to this one!
\n" ); document.write( "

Algebra.Com's Answer #162514 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
If r varies inversely with w - 1. If r = 3/50 when w = 3, find r when w is 10.
\n" ); document.write( "A75
\n" ); document.write( "B10
\n" ); document.write( "C175
\n" ); document.write( "D1/75
\n" ); document.write( "E1/750
\n" ); document.write( "F1/175
\n" ); document.write( "------------
\n" ); document.write( "r = k/(w-1) k is some constant
\n" ); document.write( "3/50 = k/(3-1) = k/2
\n" ); document.write( "k = 3/25
\n" ); document.write( "-------------------
\n" ); document.write( "r = (3/25)/(10-1)
\n" ); document.write( "r = 1/75
\n" ); document.write( "
\n" ); document.write( "
\n" );