document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=215032>Question 215032</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm actually in pre-calc...i just couldn't find a category for it.\r<BR>\n" );
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document.write( "here's my problem!\r<BR>\n" );
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document.write( "A ship travels 58 km on a bearing of 20 degrees, and then travels on a bearing of 110 degrees for 133 km. Find the distance from the starting point to the end of the trip, to the nearest kilometer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #162499 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=162499\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A ship travels 58 km on a bearing of 20 degrees, and then travels on a bearing of 110 degrees for 133 km. Find the distance from the starting point to the end of the trip, to the nearest kilometer.<BR>\n" );
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document.write( "2 sides of a triangle are given, 58 and 133 km.<BR>\n" );
document.write( "The change in heading from 020º to 110º is 90º, so it's a right triangle.<BR>\n" );
document.write( "Use Pythagoras:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s+=+sqrt%2858%5E2+%2B+110%5E2%29 ALIGN=MIDDLE  ALT=\"s+=+sqrt%2858%5E2+%2B+110%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "s = 124 km </SPAN>\n" );
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