document.write( "Question 215047: The product of two consecutive odd integers is 10 more than the square of the smaller integer. Find the integers. \n" ); document.write( "
Algebra.Com's Answer #162497 by drj(1380)\"\" \"About 
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The product of two consecutive odd integers is 10 more than the square of the smaller integer. Find the integers.\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Let n be one odd number and n+2 be the next consecutive odd number\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Let n*(n+2) be the product of the two odd integers\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Let \"n%5E2\" be the square of the smaller integer.\r
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\n" ); document.write( "\n" ); document.write( "Step 4. n*(n+2)=n^2+10 since the product of two consecutive odd integers is 10 more than the square of the smaller integer. Solve yields the following steps:\r
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\n" ); document.write( "\n" ); document.write( "\"n%2A%28n%2B2%29=n%5E2%2B10\"\r
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\n" ); document.write( "\n" ); document.write( "\"n%5E2%2B2n=n%5E2%2B10\"\r
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\n" ); document.write( "\n" ); document.write( "\"2n=10\" divide by two to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"2n=10%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"n=5\" and \"n%2B2=7\"\r
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\n" ); document.write( "\n" ); document.write( "Check \"5%2A7=5%5E2%2B10\" which is a true statement\r
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\n" ); document.write( "\n" ); document.write( "Step 5. The numbers are 5 and 7.\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful. \r
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\n" ); document.write( "\n" ); document.write( "For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
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