document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29464>Question 29464</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have tried this coin problem several ways and can't get it to add up right. Supposidly we are to answer it using the elimination method. The question is.<BR>\n" );
document.write( "Sam has a collection of nickels and dimes that is worth $5.65. If the number of dimes wer doubled and the number of nickels were increased by 8. The value of the coins would be $10.45. How many dimes does he have?<BR>\n" );
document.write( "I set it up like this. x= nickles y = dimes<BR>\n" );
document.write( "5x + 10y = 5.65<BR>\n" );
document.write( "5(x + 8) + 2(10y) = 10.45<BR>\n" );
document.write( " I came up with x = 9, and y = 44. There is no way that is right. I have spent hours on this. Please help!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16249 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16249\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SEE MY COMMENTS BELOW..<BR>\n" );
document.write( "I have tried this coin problem several ways and can't get it to add up right. Supposidly we are to answer it using the elimination method. The question is.<BR>\n" );
document.write( "Sam has a collection of nickels and dimes that is worth $5.65. If the number of dimes wer doubled and the number of nickels were increased by 8. The value of the coins would be $10.45. How many dimes does he have?<BR>\n" );
document.write( "I set it up like this. x= nickles y = dimes................GOOD<BR>\n" );
document.write( "5x + 10y = 5.65............IT SHOULD BE 565 CENTS...NOT 5.65 $..SINCE ON LHS,YOU ARE USING 5 AND 10 AS CENTS..YOU SHOULD PUT 0.05 AND 0.10 IF YOU WANT TO USE 5.65 $..CONSISTENCY OF UNITS... <BR>\n" );
document.write( "5(x + 8) + 2(10y) = 10.45...SAME COMMENT ..IT IS 1045 CENTS.ALSO BETTER WRITE 10(2Y)...TO SHOW THAT THE DIMES ARE DOUBLED,AS YOU HAVE PUT 5(X+8)TO SHOW THAT NICKELS ARE INCREASED BY 8.<BR>\n" );
document.write( "I came up with x = 9, and y = 44. There is no way that is right. I have spent hours on this. Please help!!<BR>\n" );
document.write( "SO WE HAVE 5X+10Y=565...OR DIVIDING BY 5 THROUGHOUT...<BR>\n" );
document.write( "X+2Y=113........................I<BR>\n" );
document.write( "5X+40+20Y=1045...OR.....5X+20Y=1045-40=1005......DIVIDING WITH 5...<BR>\n" );
document.write( "X+4Y=201....................II<BR>\n" );
document.write( "EQNII-EQN.I<BR>\n" );
document.write( "X+4Y-X-2Y=201-113=88<BR>\n" );
document.write( "2Y=88...OR Y=44................YOU GOT IT OK!!!!<BR>\n" );
document.write( "SUBSTITUTING IN EQN.I....<BR>\n" );
document.write( "X+2*44=113<BR>\n" );
document.write( "X=113-88=25.....YOU GOT IT WRONG HERE!!...HOW?CHECK BACK<BR>\n" );
document.write( "SO X=25 AND Y=44 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );