document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29418>Question 29418</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve and check each of the following equations for x.\r<BR>\n" );
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document.write( "x/6-x/8=1\r<BR>\n" );
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document.write( "please help.\r<BR>\n" );
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document.write( "Thank you so much. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16248 by </B><A HREF=/tutors/aboutme.mpl?userid=ikdeep><B>ikdeep(226)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikdeep><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikdeep><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x/6 - x/8 = 1\r<BR>\n" );
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document.write( "1st take the LCM of denominator i.e 6 & 8 which gives LCM = 24\r<BR>\n" );
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document.write( "on applying the LCM steps we get...\r<BR>\n" );
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document.write( "(4x -3x)/ 24 = 1\r<BR>\n" );
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document.write( "now on cross multiplying ..we get \r<BR>\n" );
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document.write( "4x - 3x = 24\r<BR>\n" );
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document.write( " x = 24\r<BR>\n" );
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document.write( "......to check you answer ,,,substitute the value of x = 24 in the given equation and we get \r<BR>\n" );
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document.write( "x/6 - x/8 = 1\r<BR>\n" );
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document.write( "24/6 - 24/8 = 1\r<BR>\n" );
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document.write( "4 - 3 = 1 \r<BR>\n" );
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document.write( "1 = 1 \r<BR>\n" );
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document.write( "LHS = RHS\r<BR>\n" );
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document.write( "Here checked or verified the answer\r<BR>\n" );
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document.write( "Please feel free to revert back for any further queries.\r<BR>\n" );
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document.write( " \r<BR>\n" );
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document.write( " </SPAN>\n" );
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