document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29458>Question 29458</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation.<BR>\n" );
document.write( "3x/x+2+7/x-2=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16243 by </B><A HREF=/tutors/aboutme.mpl?userid=ikdeep><B>ikdeep(226)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikdeep><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikdeep><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16243\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x/x+2  +7/x-2=3\r<BR>\n" );
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document.write( "take the LCM of the denominator i.e (x+2)(x-2)....and we get\r<BR>\n" );
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document.write( "[3x(x-2) + 7(x+2)]/(x+2)(x-2) = 3\r<BR>\n" );
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document.write( "In numerator we simply multiplyand we get.........\r<BR>\n" );
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document.write( "[3x^2 -6x + 7x + 14]/(x+2)(x-2) = 3\r<BR>\n" );
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document.write( "now, in denominator, we applies the identity (a+b)(a-b)= a^2 - b^2...and we get.\r<BR>\n" );
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document.write( "[3x^2 -6x + 7x + 14]/ (x)^2 - (2)^2 = 3\r<BR>\n" );
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document.write( "[3x^2 -6x + 7x + 14]/ x^2 - 4 = 3\r<BR>\n" );
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document.write( "now on cross multipication we get....\r<BR>\n" );
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document.write( " 3x^2 -6x + 7x + 14= 3(x^2 - 4 )\r<BR>\n" );
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document.write( "3x^2 + x + 14= 3x^2 - 12\r<BR>\n" );
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document.write( " x + 14 = -12 (3x^2 from both side would be cancelled).\r<BR>\n" );
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document.write( "or x = -12 -14\r<BR>\n" );
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document.write( "  x = -26\r<BR>\n" );
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document.write( ",,,,,,Now to verify our answer,,put the value x = -26,,,in the given equation and you will certainly get \"3\" as answer which is equal to RHS i.e \"3\".\r<BR>\n" );
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document.write( "Please feel free to revert back for any further queries.\r<BR>\n" );
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