document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=214961>Question 214961</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and train B is traveling at 84 miles per hour. Train A passes a station at 6:25pm. If train B passes the same station at 6:55pm., at what time will train B catch up to train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #162422 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=162422\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and train B is traveling at 84 miles per hour. Train A passes a station at 6:25pm. If train B passes the same station at 6:55pm., at what time will train B catch up to train A?<BR>\n" );
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document.write( "6:25 PM = 1855<BR>\n" );
document.write( "In 1/2 hour from 1825 to 1855, train A goes 40 miles (80 mph * 1/2 hour)<BR>\n" );
document.write( "Train B gains on Train A at 4 mph (84-80)<BR>\n" );
document.write( "40 miles at 4 mph = 10 hours<BR>\n" );
document.write( "1855 + 1000 = 0455<BR>\n" );
document.write( "4:55 AM </SPAN>\n" );
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