document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=214911>Question 214911</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of a supplement of an angle is 60 less than three times the measure of the complement of the angle. Find the measure of the angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #162380 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=162380\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let  a  =  angle<BR>\n" );
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document.write( "Let  x= complement = 90-a<BR>\n" );
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document.write( "Let  y =  supplement = 180 -a<BR>\n" );
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document.write( "y=3x -60,,,,,subst<BR>\n" );
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document.write( "(180-a) = 3(90-a) - 60<BR>\n" );
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document.write( "180-a = 270 -3a -60<BR>\n" );
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document.write( "180 +60 -270 = a-3a<BR>\n" );
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document.write( "-30 = -2a<BR>\n" );
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document.write( "a=15<BR>\n" );
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document.write( "x= 90-15=75<BR>\n" );
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document.write( "y= 180-15=165<BR>\n" );
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document.write( "165 = 3(75)-60,,,,ok<BR>\n" );
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