document.write( "Question 214875: A car leaves Oak Corners at 11:30 AM traveling south at 60 mph. At the same time, another car is 50 miles west of Oak Corners traveling east at 40 mph. Express the distance d between the cars as a function of the time t after the first car left Oak Corners. \n" ); document.write( "
Algebra.Com's Answer #162372 by Alan3354(69443)\"\" \"About 
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A car leaves Oak Corners at 11:30 AM traveling south at 60 mph. At the same time, another car is 50 miles west of Oak Corners traveling east at 40 mph. Express the distance d between the cars as a function of the time t after the first car left Oak Corners.
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\n" ); document.write( "It's not clear which is the \"1st car\", but starting from the time one car is 50 miles west (1130):
\n" ); document.write( "d^2 = (50 - 40t)^2 + (60t)^2
\n" ); document.write( "d^2 = 2500 - 4000t + 1600t^2 + 3600t^2
\n" ); document.write( "d^2 = 5200t^2 - 4000t + 2500
\n" ); document.write( "d(t) = 10sqrt(52t^2 - 40t + 25) t in hours, d in miles
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