document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=214900>Question 214900</A>: <I><SPAN STYLE=\"word-break: break-all;\"> convert the following equations into logrimithic form\r<BR>\n" );
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document.write( "6=2x\r<BR>\n" );
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document.write( "-9=6y\r<BR>\n" );
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document.write( "7=3y\r<BR>\n" );
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document.write( "x=5y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #162355 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=162355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> convert the following equations into logrimithic form <BR>\n" );
document.write( "6=2^x<BR>\n" );
document.write( "log(base 2) 6 = x<BR>\n" );
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document.write( "-9=6^y<BR>\n" );
document.write( "log(base 6) -9 = y<BR>\n" );
document.write( "Comment: That is meaningless as no power of 6 can give you a negative number.<BR>\n" );
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document.write( "7=3^y<BR>\n" );
document.write( "log(base 3) 7 = y<BR>\n" );
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document.write( "x=5^y<BR>\n" );
document.write( "log(base 5) x = y<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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