document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=214880>Question 214880</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 147. The second number is 4 more than two times the first number. The third number is five less than three times the first number. Find the three numbers. \r<BR>\n" );
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document.write( "Please help me solve this problem. I tried to do it a few times but I get confused right off the bat. Thanks for any help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #162346 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=162346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y+Z=147<BR>\n" );
document.write( "Y=2X+4<BR>\n" );
document.write( "Z=3X-5<BR>\n" );
document.write( "X+(2X+4)+(3X-5)=147<BR>\n" );
document.write( "6X-1=147<BR>\n" );
document.write( "6X=147+1<BR>\n" );
document.write( "6X=148<BR>\n" );
document.write( "X=148/6<BR>\n" );
document.write( "X=24 2/3 ANS. ANS<BR>\n" );
document.write( "Y=2*24 2/3+4=49/3+4=53 1/3 ANS<BR>\n" );
document.write( "Z=3*24 2/3-5=74-5=69 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "24 2/3+53 1/3+69=147<BR>\n" );
document.write( "147=147<BR>\n" );
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