document.write( "Question 214894: I need help solving the quadratic function,For Each Funtion:(a) determine whether the graph opens down or up, (b) find the axis of symmetry, (c)find the vertex, (d)find the y-intercept,(e) find the zeros, and (f) graph the function
\n" ); document.write( "the equation is: -x(x-3)
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Algebra.Com's Answer #162342 by Earlsdon(6294)\"\" \"About 
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For:
\n" ); document.write( "\"-x%28x-3%29\" rewrite as \"y+=+-x%5E2%2B3x\"
\n" ); document.write( "Find:
\n" ); document.write( "a) The graph opens downward as indicated by the negative value of the \"x%5E2\" term.
\n" ); document.write( "b) The axis of symmetry (AOS) is given by:
\n" ); document.write( "\"x+=+-b%2F2a\" where: a = -1 and b = 3.
\n" ); document.write( "\"x+=+%28-3%29%2F2%28-1%29\"
\n" ); document.write( "\"highlight%28x+=+3%2F2%29\" This is the equation of the AOS.
\n" ); document.write( "c) The vertex is lies on the AOS and is found by using the equation of the AOS for the x-coordinate, then substituting this into the given quadratic equation to solve for the corresponding y-coordinate.
\n" ); document.write( "\"y+=+-x%5E2%2B3x\" Substitute \"x+=+3%2F2\"
\n" ); document.write( "\"y+=+-%283%2F2%29%5E2%2B3%283%2F2%29\" Evaluate.
\n" ); document.write( "\"y+=+-%289%2F4%29%2B%289%2F2%29\"
\n" ); document.write( "\"y+=+9%2F4\"
\n" ); document.write( "The vertex is at: (3/2, 9/4)
\n" ); document.write( "d)
\n" ); document.write( "The y-intercept is found by setting x = 0 in the given quadratic equation and solving for y.
\n" ); document.write( "\"y+=+-x%5E2%2B3x\" Substitute x = 0.
\n" ); document.write( "\"y+=+0\"
\n" ); document.write( "The y-intercept is at: (0, 0)
\n" ); document.write( "e)
\n" ); document.write( "The zeros are found by setting the given quadratic equation equal to zero and solving.
\n" ); document.write( "\"-x%5E2%2B3x+=+0\" Factor a -x.
\n" ); document.write( "\"-x%28x-3%29+=+0\" Apply the zero product rule:
\n" ); document.write( "\"-x+=+0\" or \"x-3+=+0\" so that...
\n" ); document.write( "\"highlight%28x+=+0%29\" or \"highlight%28x+=+3%29\"
\n" ); document.write( "The zeros are at (0, 0) and (3, 0)
\n" ); document.write( "f)
\n" ); document.write( "Graph: \"y+=+-x%5E2%2B3x\"
\n" ); document.write( "\"graph%28400%2C400%2C-5%2C5%2C-5%2C5%2C-x%5E2%2B3x%29\"
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