document.write( "Question 214890: Please help me this word problem: Kevin drove 320 miles to a mountain resort. His return trip took 20 minutes longer because his speed returning was 4 mi/h slower than his speed going. \r
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Algebra.Com's Answer #162341 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "320=RT OR R=320/T \n" ); document.write( "320=(R-4)(T+1/3) \n" ); document.write( "320=(320/T-4)(T+1/3) \n" ); document.write( "320=320-4T+320/3T-4/3 \n" ); document.write( "-4T+320/3T-4/3=0 \n" ); document.write( "(-4T*3T+320-4T)/3T=0 \n" ); document.write( "(-12T^2+320-4T)/3T=0 \n" ); document.write( "12T^2+4T-320=0 \n" ); document.write( "4(3T^2+T-80)=0 \n" ); document.write( " \n" ); document.write( "T=(-1+-SQRT[1^1-4*3*-80])/2*3 \n" ); document.write( "T=(-1+-SQRT[1+960])/6 \n" ); document.write( "T=(-1+-SQRT961)/6 \n" ); document.write( "T=(-1+-31)/6 \n" ); document.write( "T=-32/3=-5.333 \n" ); document.write( "T=(-1+31)/6 \n" ); document.write( "T=30/6 \n" ); document.write( "T=5 HRS. GOING. \n" ); document.write( "PROOF; \n" ); document.write( "320=R*5 \n" ); document.write( "R=320/5 \n" ); document.write( "R=64 MPH. GOING \n" ); document.write( "320=(64-4)(5+1/3) \n" ); document.write( "320=60*16/3 \n" ); document.write( "320=960/3 \n" ); document.write( "960=960 \n" ); document.write( " \n" ); document.write( " |