document.write( "Question 214890: Please help me this word problem: Kevin drove 320 miles to a mountain resort. His return trip took 20 minutes longer because his speed returning was 4 mi/h slower than his speed going. \r
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Algebra.Com's Answer #162332 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! Velocity = Distance / Time,,,,or T = D/V \n" ); document.write( ". \n" ); document.write( "(1) T1 = 320 / V1 \n" ); document.write( ". \n" ); document.write( "(2) T2 = 320 / V2,,,,,but T2 = T1 + 20/60 (hrs) ,,,and V2 = V1 -4 \n" ); document.write( ". \n" ); document.write( "subst in (2) \n" ); document.write( ". \n" ); document.write( "{ T1 + 20/60} = 320 / {V1-4},,,and T1 = 320 /V! \n" ); document.write( ". \n" ); document.write( "{ (320/V1) +20/60 } = 320 /{V1-4) \n" ); document.write( ". \n" ); document.write( "Multiply thru by (3) V1(V1-4) \n" ); document.write( ". \n" ); document.write( "(320 (3) (V1-4) + 1(V1)(V1-4) = 320 (3)(V1) \n" ); document.write( ". \n" ); document.write( "960 V1 - 3840 + V1^2 -4V1 = 960V1 \n" ); document.write( ". \n" ); document.write( "v1^2 -4V1 -3840 =0,,,,,factor \n" ); document.write( ". \n" ); document.write( "(V1 -64)(V1+60) =0 \n" ); document.write( ". \n" ); document.write( "V1= 64, -60 ( not practical) \n" ); document.write( ". \n" ); document.write( "check,,,V1= 64,,,V2 = 60 \n" ); document.write( ". \n" ); document.write( "T1 = 320 /64 = 5 hrs \n" ); document.write( ". \n" ); document.write( "T2 = 5 hrs + 1/3 hr = 5.33 hrs \n" ); document.write( ". \n" ); document.write( "T2 = 320 / 60 = 5.333,,,,,ok \n" ); document.write( ".\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |