document.write( "Question 29439: x^2+x<12 \n" ); document.write( "
Algebra.Com's Answer #16232 by Bb(20)\"\" \"About 
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ok 1st u simplify the problem 2x^2<12=4x<12 then u divide by 4 on each side and u get x<4 to chek u replace the x with 3 so u get 3^2+3<12\r
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