document.write( "Question 214835: Wondering if I am heading in the right direction. My question is:\r
\n" ); document.write( "\n" ); document.write( " Is f(x)=x^1171 - 5x^109 + 3 y-axis symmetric, origin symmetric or neither.\r
\n" ); document.write( "\n" ); document.write( "When I plug (-x) into the equation it does not come out to be y-axis symmetric and when I multiple each side by (-1) it does not come out to be origin symmetric. So, my answer is neither.\r
\n" ); document.write( "\n" ); document.write( "Am I figuring this out correctly?\r
\n" ); document.write( "\n" ); document.write( "Lori \n" ); document.write( "

Algebra.Com's Answer #162310 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
You are correct. When working with polynomials, the graph will be y-axis symmetric if EVERY exponent is an even exponent. Since there are no even exponents, it's not y-axis symmetric. On the other hand, the graph will be origin symmetric only if EVERY exponent is an odd exponent. Since $\"3=3x%5E0\"$ has an even exponent (not odd), this rules out symmetry with respect to the origin as well. If the function was $\"f%28x%29=x%5E1171+-+5x%5E109\"$ , then you'd find that the graph was symmetric to the origin (go ahead and test it if you want). \n" ); document.write( "

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