document.write( "Question 214826: A father is three times as old as his son. In 14 years' time, he will be twice as old as his son. How old is the father now? \n" ); document.write( "
Algebra.Com's Answer #162302 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! Let F=fathers age now,,,,and S= son's age now \n" ); document.write( ". \n" ); document.write( "(1) F=3s \n" ); document.write( ". \n" ); document.write( "(2) (F+14) = 2(S+14) \n" ); document.write( ". \n" ); document.write( "F+14 = 2S +28 \n" ); document.write( ". \n" ); document.write( "subst from (1),,,,(3S) +14 = 2s +28 \n" ); document.write( ". \n" ); document.write( "S= 14,,,,,and F=3(14) =42 \n" ); document.write( ". \n" ); document.write( "checking,,,(42 +14) = 2(14) + 28 \n" ); document.write( ". \n" ); document.write( "56 = 56,,,,ok \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |