document.write( "Question 214792: Phillip has 10 coins in his pocket. Phillip has the same number of pennis as quarter and the same number of dimes as nickels. He also has one more nickel than he does pennies. If he has 97 cent how many coins of each type does he have? \n" ); document.write( "
Algebra.Com's Answer #162283 by ankor@dixie-net.com(22740)\"\" \"About 
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Phillip has 10 coins in his pocket.
\n" ); document.write( " Phillip has the same number of pennies as quarters and the same number of dimes as nickels.
\n" ); document.write( "He also has one more nickel than he does pennies.
\n" ); document.write( " If he has 97 cent how many coins of each type does he have?
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\n" ); document.write( "Let x = no. of pennies & quarters
\n" ); document.write( "Let y = no. of dimes & nickels
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\n" ); document.write( "\"He has one more nickel than pennies
\n" ); document.write( "y = x + 1
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\n" ); document.write( "Total no. of coins
\n" ); document.write( "2x + 2y = 10
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "x + y = 5
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\n" ); document.write( "we know: y = x+1
\n" ); document.write( "therefore
\n" ); document.write( "x = 2 ea pennies & quarters
\n" ); document.write( "y = 3 ea nickels & dimes
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\n" ); document.write( "Check using $amt
\n" ); document.write( ".01(2) + .25(2) + .05(3) + .10(3) =
\n" ); document.write( ".02 + .50 + .15 + .30 = .97\r
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