document.write( "Question 214806: Solve the problem. Please show your work.\r
\n" ); document.write( "\n" ); document.write( "1. The population of a colony of bacteria is decaying exponentially according to the function below, where t is the time in minutes. How many minutes will it take for the population of the colony to drop to 50?\r
\n" ); document.write( "\n" ); document.write( "B(t)=2000*e^(-.03*t)\r
\n" ); document.write( "\n" ); document.write( "e=2.718
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Algebra.Com's Answer #162268 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
\"B%28t%29=2000%2Ae%5E%28-.03%2At%29\"
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\n" ); document.write( "Substitute 50 for B(t) to get:
\n" ); document.write( "\"50+=+2000%2Ae%5E%28-.03%2At%29\"
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\n" ); document.write( "Take the natural log of both sides to get:
\n" ); document.write( "\"ln%2850%29+=+ln%282000%2Ae%5E%28-.03%2At%29%29\"
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\n" ); document.write( "rules of logarithms apply here.
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\n" ); document.write( "first rule:
\n" ); document.write( "\"ln%28a%2Ab%29+=+ln%28a%29+%2B+ln%28b%29\"
\n" ); document.write( "second rule:
\n" ); document.write( "\"ln%28a%5Eb%29+=+b%2Aln%28a%29\"
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\n" ); document.write( "applying the first rule,
\n" ); document.write( "\"ln%282000%2Ae%5E%28-.03%2At%29%29\" becomes \"ln%282000%29+%2B+ln%28e%5E%28-.03t%29%29\"
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\n" ); document.write( "applying the second rule,
\n" ); document.write( "\"ln%28e%5E%28-.03t%29%29\" becomes \"-.03t%2Aln%28e%29\"
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\n" ); document.write( "putting this all together, your equation becomes:
\n" ); document.write( "\"ln%2850%29+=+ln%282000%29+-+.03t%2Aln%28e%29\"
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\n" ); document.write( "\"ln%28e%29\" equals 1, so your equation becomes:
\n" ); document.write( "\"ln%2850%29+=+ln%282000%29+-+.03t\"
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\n" ); document.write( "subtract ln(2000) from both sides of this equation and then divide both sides of this equation by (-.03) to get:
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\n" ); document.write( "\"%28ln%2850%29+-+ln%282000%29%29%2F%28-.03%29+=+t\"
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\n" ); document.write( "this becomes:
\n" ); document.write( "\"%283.912023005+-+7.60090246%29%2F%28-.03%29+=+t\"
\n" ); document.write( "this becomes:
\n" ); document.write( "\"122.9626485+=+t\"
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\n" ); document.write( "The population will decay to 50 in 122.9626485 hours.
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\n" ); document.write( "substitute this value for t in the original equation to get:
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\n" ); document.write( "\"B%28t%29=2000%2Ae%5E%28-.03%2A%28122.9626485%29%29\"
\n" ); document.write( "this becomes:
\n" ); document.write( "\"B%28t%29+=+50\" confirming that \"t+=+122.9626485\" is a good value for t.
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