document.write( "Question 214809: the sum of twelve and an unknown number is four times the unknown number. \n" ); document.write( "
Algebra.Com's Answer #162266 by Theo(13342)\"\" \"About 
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x is the unknown number
\n" ); document.write( "12 + x = 4*x
\n" ); document.write( "subtract x from both sides of this equation to get:
\n" ); document.write( "12 = 3*x
\n" ); document.write( "divide both sides of this equation by 3 to get:
\n" ); document.write( "4 = x which is the same as:
\n" ); document.write( "x = 4
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\n" ); document.write( "let x = 4 in your original equation.
\n" ); document.write( "12 + 4 = 4*4 becomes:
\n" ); document.write( "16 = 16 confirming that x = 4 is a good number.
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