document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=214783>Question 214783</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A conical tank is 12 feet deep and the diameter of the top is 8 feet. If the tank is filled with water to a depth of 7 feet, what is the area of the surface of the water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #162246 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=162246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A  rough  sketch  might  add  to  visual  understanding<BR>\n" );
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document.write( "Cone  pointed  down.  Height  is  12 top  dia  is  8.,,,,,,,  7  feet  from  bottom area  is  ?<BR>\n" );
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document.write( "8/12 = x/7,,,,,where  x  is  dia <BR>\n" );
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document.write( "cross  multiply,,,12x = 56,,,,,,x=4.67  ft   in  dia<BR>\n" );
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document.write( "Area  =  pi*r^2 = pi* 4.67^2 = 68.42 sq ft<BR>\n" );
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