document.write( "Question 29427: log( base 2) x + log (base 4) x = 3 \n" ); document.write( "
Algebra.Com's Answer #16223 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
log( base 2) x + log (base 4) x = 3
\n" ); document.write( "log(base 2)x = 3 - log(base 4)x
\n" ); document.write( "4^(log(base 2)x = 4^(3 - log(base 4)x)
\n" ); document.write( "2^(log(base 2)x * 2^(log(base 2)x = 4^3 / 4^log(base 4)x
\n" ); document.write( "x^2 = 4^3 / x
\n" ); document.write( "\"x%5E3+=+4%5E3\"
\n" ); document.write( "\"x+=+4\"
\n" ); document.write( "check
\n" ); document.write( "log(base 2)4 + log(base 4)4 = 3
\n" ); document.write( "\"2+%2B+1+=+3\"
\n" ); document.write( "
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