document.write( "Question 3606: A guy has 30 coins consisting of nickels dimes and quarters. He has 3 more dimes than nickels. The total of the coins is $3.55. find the number of quarters. (I have done problems like this before without any problems but this one is giving me a really hard time. It seems simple but i cant get the correct solution..??? \n" ); document.write( "
Algebra.Com's Answer #1622 by AnlytcPhil(1806)\"\" \"About 
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A guy has 30 coins consisting of nickels dimes and quarters. He has 3 more
\n" ); document.write( "dimes than nickels. The total of the coins is $3.55. Find the number of
\n" ); document.write( "quarters. (I have done problems like this before without any problems but this
\n" ); document.write( "one is giving me a really hard time. It seems simple but I can't get the
\n" ); document.write( "correct solution..???
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\n" ); document.write( ">>...a guy has 30 coins consisting of nickels dimes and quarters...<<
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\n" ); document.write( "` ` ` ` ` ` ` ` `N + D + Q = 30
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\n" ); document.write( ">>...he has 3 more dimes than nickels...<<
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\n" ); document.write( "` ` ` ` ` ` ` ` ` ` ` ` `D = N + 3
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\n" ); document.write( ">>...The total money value of the coins is $3.55...<<
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\n" ); document.write( "` `$0.05N + $0.10D + $.25Q = $3.55
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\n" ); document.write( "Dropping the dollar marks and multiplying thru by 100:
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\n" ); document.write( "` ` ` ` ` ` 5N + 10D + 25Q = 355
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\n" ); document.write( "Since all those terms can be easily divided by 5, we can
\n" ); document.write( "simplify it to
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\n" ); document.write( "` ` ` ` ` ` ` `N + 2D + 5Q = 71
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\n" ); document.write( "Now we have this system of equations:
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\n" ); document.write( "` ` ` N + D + Q = 30
\n" ); document.write( "` ` ` ` ` ` ` D = N + 3
\n" ); document.write( "` ` N + 2D + 5Q = 71\r
\n" ); document.write( "\n" ); document.write( "Can you solve this system of equations? If not post again.
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\n" ); document.write( "Answer:10 nickels, 13 dimes 7 quarters
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\n" ); document.write( "Edwin
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