document.write( "Question 214689: I need to find the surface area of the inside of a dry pond in the shape of an oval. The length is 107 ft. The Width is 41 ft. And it is 5 ft deep. Please help me find the suface area of this oval shaped dry pond. \n" ); document.write( "
Algebra.Com's Answer #162147 by Earlsdon(6294)\"\" \"About 
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You can do this in two steps:
\n" ); document.write( "1). Find the area of the oval (elliptical) bottom of the dry pool.
\n" ); document.write( "2). Find the inside area of the oval-shaped side.
\n" ); document.write( "Add these together to get total inside surface area.
\n" ); document.write( "1) The area of an ellipse is given by:
\n" ); document.write( "\"A+=+%28pi%29%2Aa%2Ab\" where a = the length of the semi-major axis and b = the length of the semi-minor axis.
\n" ); document.write( "In this pool, the semi-major axis (a) is 107/2 = 53.5ft.
\n" ); document.write( "The length of the semi-minor axis (b) is 41/2 = 20.5ft.
\n" ); document.write( "\"A+=+%28pi%29%2853.5%29%2820.5%29\"
\n" ); document.write( "\"highlight_green%28A+=+3445.5%29\"sq.ft.
\n" ); document.write( "2) The area of the of the iside of the elliptical-shaped pool by multplying the circumference of the pool by the depth of the pool.
\n" ); document.write( "The approximate circumference (C) of the elliptical pool is given by:
\n" ); document.write( "\"C+=+2%28pi%29sqrt%28%28a%5E2%2Bb%5E2%29%2F2%29\"
\n" ); document.write( "\"a%5E2+=+53.5%5E2\"
\n" ); document.write( "\"a%5E2+=+2862.25\"
\n" ); document.write( "\"b%5E2+=+20.5%5E2\"
\n" ); document.write( "\"b%5E2+=+420.25\"
\n" ); document.write( "\"C+=+2%28pi%29sqrt%28%282862.25%2B420.25%29%2F2%29\"
\n" ); document.write( "\"C+=+254.55\"
\n" ); document.write( "Now multiply this by the depth of the pool (\"d+=+5\"ft.)
\n" ); document.write( "\"C%2Ad+=+%28254.55%29%2A%285%29\"=\"highlight_green%281272.75%29\"sq.ft. This is the area of the inside wall of the pool. Add the two areas to get the total surface area (S) of the inside of the dry pool.
\n" ); document.write( "\"S+=+3445.5%2B1272.75\"
\n" ); document.write( "\"highlight%28S+=+4718%29\"sq.ft.
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